Question 685863
Two cars leave towns 640 kilometers apart at the same time and travel toward each other. One car's rate is 10 kilometers per hour more than the other's. If they meet in 4 hours, what is the rate of the faster car?
**
let x=rate of speed of faster car
x-10=rate of speed of slower  car
distance=rate of speed*travel time
4x+4(x-10)=640
4x+4x-40=640
8x=680
x=85
rate of speed of faster car= 85km/hr