<PRE><B>Question 685664</B>
A committee of two persons is selected from two men and two women.
Find the probability that the committee will have at least one man.
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Note: P(2 women chosen) = 2C2/4C2 = 1/6
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Your Problem:
P(at least one man) = 1 - P(2 women) = 1-(1/6) = 5/6
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Cheers,
Stan H.</PRE>