Question 685690
let the length be x
so the length is decreased by 5%

(x-(5/100)*x) is the new length

=95x/100

let breadth be y

it is increased by 5%

so the new breadth = y+(5y/100) = 105y/100

Area after the change = 95x/100 * 105y/100

Area before the change = xy

change in area 

{{{xy - ((95x*105y)/10000)}}}

={{{25xy/100000 }}}

change in  area/ area before change *100 = percentage change

{{{25xy/100000}}}/{{{xy}}} *100

0.025% change