Question 61683
THE SECOND ANGLE OF A TRIANGLE IS TWO TIMES AS LARGE AS THE FIRST.THE THIRD ANGLE IS 10 DEGREES MORE THAN THE SECOND ANGLE. FIND THE MEASURE OF THE FIRST ANGLE.

Let the first angle = A.
Then, the second angle = 2A.
The third angle = 2A+10.
The 3 angles add up to 180 (for all triangles.)

So, {{{A+2A+(2A+10) = 180}}}.
Or, {{{5A+10 = 180}}}.
Or, {{{5A=170}}}.
Or, {{{A=170/5 = 34 degrees}}}.

Verification:

First angle = 34.
Second angle = 2*first angle = 68.
Third angle = second angle + 10 = 78.

The three angles add up to 34+68+78 = 180.