Question 685172
Evaluate and get exact answer for:
{{{ 10^x + 10^(-x) = 48 }}}
{{{ 10^(2x) + 1 = 48*10^x }}}
{{{ 10^(2x) - 48*10^x + 1 = 0}}}
u = 10^x
{{{u^2 - 48u + 1 = 0}}}
*[invoke solve_quadratic_equation 1,-48,1]
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10^x = 24 + sqrt(575)
x = log(24 + sqrt(575))
x = log(24 - sqrt(575))