Question 684669
{{{(h-20)/(h^2-16) + 2/(h-4)}}}
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{{{(h-20)/((h+4)(h-4)) + (2/(h-4))((h+4)/(h+4))}}}
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{{{((h-20)+2(h+4))/(h^2-16)}}}
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{{{(h-20+2h+8)/(h^2-16)}}}
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{{{(3h-12)/(h^2-16) = (3(h-4))/((h+4)(h-4)) = highlight_green(3/(h+4))}}}
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