Question 684824
(fog) = {{{sqrt(4(4x^2-2)+1)}}}
= {{{sqrt(16x^2-8+1)}}}
= {{{sqrt(16x^2-7)}}}
(fog)(1) = {{{sqrt(16(1)^2-7)}}}
= {{{sqrt(16-7)}}}
= {{{sqrt(9)}}}
(fog)(1) = 3
...
...
(gof) = {{{4(sqrt(4x+1))^2-2}}}
= 4(4x+1)- 2
= 16x + 4 - 2
= 16x + 2
(gof)(6) = 16*6 + 2
= 96 + 2
(gof)(6) = 98
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