Question 61644
Square root of 3+2i
---------------------divided by
Square root of 3-2i
--------------
Multiply numerator and denominator by sqrt(3-2i) to get:
[sqrt[(3+2i)(3-2i)]/(3-2i)
=[sqrt(9+4)]/(3-2i)
=[sqrt(13)]/(3-2i)
Multiply numerator and denominator by (3+2i) to get:
=[(sqrt13)/13][3+2i]
Cheers,
Stan H.