Question 684903
ln x^-3 - (ln x)^2 = -28
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If you mean ln(x^-3) and (ln(x))^2
-3ln(x) - (ln x)^2 = -28
(ln(x))^2 + 3ln(x) - 28 = 0
sub u for ln(x)
{{{u^2 + 3u - 28 = 0}}}
(u + 7)*(u - 4) = 0
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ln(x) = -7
{{{x = e^(-7)}}}
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ln(x) = 4
{{{x = e^4}}}