Question 684473
{{{(3x^2y^4z^-2)/(6x^-1y^3z^-3)}}}
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{{{((3x^2y^4)/(z^2))/((6y^3)/(xz^3)) = ((3x^2y^4)/(z^2))((xz^3)/(6y^3))}}}
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{{{(3x^3y^4z^3)/(6y^3z^2) = (x^3yz)/(2)}}}
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OR subtract exponents when dividing
{{{(3x^2y^4z^-2)/(6x^-1y^3z^-3)}}}
{{{x^(2--1)y^(4-3)z^(-2--3) = x^3y^1z^1}}}
{{{(x^3yz)/2}}}
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