Question 684486
{{{f^-1(x)}}} solve for x
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y = {{{5x^3+2}}}
{{{y - 2 = 5x^3}}}
{{{(y-2)/5 = x^3}}}
{{{root(3,(y-2)/5) = root(3,x^3)}}}
x = {{{root(3,(y-2)/5) = ((y-2)/5)^(1/3)}}}
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{{{f^-1(x) = ((x-2)/5)^(1/3)}}}
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no g(x) is not an inverse, unless you mistyped x-3 instead of x-2
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