Question 61609
{{{g(x) = (x - 3) / (x^2 - x - 6)}}}
{{{g(x) = (x - 3) / (x + 2)(x - 3)}}}
{{{g(x) = 1 / (x + 2)}}}
x can have any value except -2. That would make the denominator 0. Division
by zero is not allowed.