Question 684328
For each right triangle find all the missing values of the side lengths and angle measures.Show your work 
a) Triangle PQR is right angled at Q , PQ is 24 cm, RQ is 10 cm , PQ is the hypotenuse which is unknown.
PQ = sqrt[24^2+10^2] = sqrt(576] = 26
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b) Triangle PRQ is right angled at R, PQ is 30 mm , RQ is 40 mm , PQ is 50 mm.
P is the angle opposite RQ 
PQ is opposite R and is the hypotenuse
So P = sin^-1(40/50) = 53.13 degrees
And Q = sin^-1(30/50) = 36.87 degrees

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c) Triangle QRP is right angled at R , angle of P is 60 degrees, QP is 20 cm. 
can you please explain this to me? thanks in advance 
Draw the picture.
You have a right triangle with 
hypotenuse is side opposite right angle R which is QP = 20 cm
P = 60 degrees is the angle opposite QR
Q = 90-60 = 30 degrees
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QR is side opposite P, so sin(P) = QR/QP ; sin(60) = QR/20 ;
QR = 20*sin(60) = 17.32
PR is side opposite Q which is 30 degrees
PR = (1/2)*hypotenuse = (1/2)*20 = 10 cm
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d) Triangle PQR is right angled at Q , QR is 1.125 dm, PR is 5.125 dm.
Draw the picture and see if you can determine:
angle P = 
angle R = 
side PQ = 
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Cheers,
Stan H.
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