Question 684302
{{{dimes=n+3}}}
{{{quarters=2(n+3)+6}}}
{{{n+n+3+2(n+3)+6=5.05}}}
or in cents

{{{ 25q + 10d + 5n = 505 }}} ( in cents )
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plug in  {{{ q = 2(n+3)+6}}} and  {{{ d = n+3 }}} and solve for {{{n}}}


{{{ 25(2(n+3)+6) + 10(n+3)+ 5n = 505 }}} 
 
{{{ 25(2n+6+6) + 10(n+3)+ 5n = 505 }}} 

{{{ 25(2n+12) + 10(n+3)+ 5n = 505 }}} 

{{{ 50n+300 + 10n+30+ 5n = 505 }}}  

{{{ 65n+330 = 505 }}}  

{{{ 65n = 505 -330}}}  

{{{ 65n = 175}}}  

{{{n=2.6923076923076923076923076923077}}}.......this and doesn't make sense, {{{n}}} should be whole number


possible solution:

{{{n=3}}}
{{{d=4}}}
{{{q=18}}}

but it doesn't match given data