Question 61484
Let's use substitution.  First, divide both sides of both equations by 2 and we get 2x-3y=6 and x+y=3.  Solve for x in the 2nd equation, we get x=3-y.  Substitute 3-y for x in the first equation and get:  2(3-y)-3y=6.  That expands to 6-2y-3y=6, and that simplifies to 6-5y=6.  Solving for y, we get y=0.  To find the value of x, substitute 0 for y in x+y=3; that yields x+0=3, or x=3.  To check our answer of (0,3), substitute that into the first equation:  2*3-3*0=6, which simplifies to 6=6, a true statement.  That means our answer is correct!