Question 684258


what is {{{x}}} in {{{-5(1+2n)=15}}}...here you have variable {{{n}}}, not {{{x}}}

we can solve for {{{n}}}


{{{-5(1+2n)=15}}}.....first multiply by {{{-5}}}

{{{-5*1+(-5)*2n=15}}}

{{{-5-10n=15}}}......add {{{10n}}} to both sides


{{{-5-10n+10n=15+10n}}}

{{{-5-cross(10n)+cross(10n)=15+10n}}}

{{{-5=15+10n}}}......add {{{-15}}} to both sides

{{{-5-15=15-15+10n}}}

{{{-5-15=cross(15)-cross(15)+10n}}}

{{{-20=10n}}}

{{{-20/10=n}}}

{{{highlight(-2=n)}}}