Question 684177
if 5th term of an AP is equal to 19 times the 19th term show that the 24th term of an AP is zero

I think the problem should be

if 5 times the 5th term of an AP is equal to 19 times the 19th term show that the 24th term of an AP is zero

T5 = a+4d
t19= a+18d

5(a+4d)=19(a+18d)	
	
5a +20d=19a+342d	
	
14a+322d=0	
	
14(a+23d)=0
a+23d=0
..
.	
	
t24= a+23d	
 But a+23d=0

therefore	
T24=0