Question 684205
given
x = -1
x = 6+i
known, but not given
x = 6-i
...
x = -1
x + 1 = 0
...
x = 6 +/- i
x - 6 = +/- {{{sqrt(-1)}}}
{{{(x-6)^2 = sqrt(-1)^2}}}
{{{(x-6)^2 = -1
{{{(x-6)^2 + 1 = 0}}}
{{{x^2 - 12x + 36 + 1 = 0}}}
{{{x^2 - 12x + 37 = 0}}}
...
{{{(x+1)(x^2-12x+37)=0}}}
{{{x^3 - 12x^2 + 37x + x^2 + 12x + 37 = 0}}}
...
{{{highlight_green(x^3 - 11x^2 + 49x + 37 = 0)}}}
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