Question 61587
Merlin has 20 coins in quarters and dimes. The total value of the coins is $3.95. How many coins of each kind does he have?
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Let number of dimes be "x"; value of these is 10x cents
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The number of quarters is "20-x" ; value of these is 25(20-x)=500-25x cents
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EQUATION:
value + value = 395 cents
10x+500-25x=395
-15x=-105
x=7 (number of dimes)
20-x=13 (number of quarters)
Cheers,
stan H.