Question 683895
{{{2(n+12)=2(n+9)+6}}} Start with the given equation.



{{{2n+24=2n+18+6}}} Distribute.



{{{2n+24=2n+24}}} Combine like terms on the right side.



{{{2n=2n+24-24}}} Subtract {{{24}}} from both sides.



{{{2n-2n=24-24}}} Subtract {{{2n}}} from both sides.



{{{0n=24-24}}} Combine like terms on the left side.



{{{0n=0}}} Combine like terms on the right side.



{{{0=0}}} Simplify.



Since this equation is <font size=4><b>always</b></font> true for any n value, this means n can equal any number. So there are an infinite number of solutions.


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{{{3(2h+1)-2(h-4)=21}}} Start with the given equation.



{{{6h+3-2h+8=21}}} Distribute.



{{{4h+11=21}}} Combine like terms on the left side.



{{{4h=21-11}}} Subtract {{{11}}} from both sides.



{{{4h=10}}} Combine like terms on the right side.



{{{h=(10)/(4)}}} Divide both sides by {{{4}}} to isolate {{{h}}}.



{{{h=5/2}}} Reduce.



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Answer:


So the solution is {{{h=5/2}}}