Question 683900
5(x–2)^2=3
Expand
{{{5(x^2-4x+4)=3}}}
Distribute
{{{5x^2-20x+20=3}}}
Subtract
{{{5x^2-20x+17=0}}}
*[invoke quadratic "x", 5, -20, 17 ]
Simplify
{{{(20+-sqrt(60))/10}}}
==>
{{{(10+-sqrt(15))/5}}}
Thus 
x= {{{(10+-sqrt(15))/5}}} or {{{2.77}}},{{{1.22}}}