Question 683687
Write an equation for the ellipse 
Eccentricity 3/4; foci (0,-2) (0,2)
This is an ellipse with vertical major axis.
its standard form of equation: {{{(x-h)^2/b^2+(y-k)^2/a^2=1}}}, a>b, (h,k)=(x,y) coordinates of center
For given ellipse:
center: (0,0)
c=2 (center to focus)
c^2=4
eccentricity:=3/4=c/a
a=4c/3=16/3
a^2=256/9
c^2=a^2-b^2
b^2=a^2-c^2=256/9-4=256/9-36/9=220/9
Equation: 
{{{9x^2/220+9y^2/256=1}}}