Question 683710
From where you left off, substitute...
{{{x^2 + (11-x)^2 = 61}}}
{{{x^2+121-22x+x^2 =61}}}
{{{2x^2 - 22x + 121-61=0}}}
{{{2x^2-22x+60=0}}} ==> divide the entire equation by 2
{{{x^2-11x +30}}}
(x-6)(x-5)=0
x-6=0, so x=6
AND
x-5=0, so x=5
... 
The numbers are 5 and 6.
... 
check
25+36=61 and 5+6=11
...
-Reading Boosters