Question 683403
Solve the equation for (theta) over the interval [0(degrees),360(degrees)). If necessary, round your answers to the nearest tenth.
{{{ 3sec(theta) - 2sqrt(3) = 0 }}}
3secx-2&#8730;3) = 0
secx=2&#8730;3/3
cosx=1/secx=3/(2&#8730;3)=&#8730;3/2
x=30º, 300º (in quadrants I and IV where cos>0)