Question 683386

{{{(3c+2)^2 -(3c-2)^2}}}


={{{(3c)^2+12c+4 -((3c)^2-12c+4)}}}


={{{(3c)^2+12c+4 -(3c)^2+12c-4}}}


={{{cross((3c)^2)+12c+cross(4) -cross((3c)^2)+12c-cross(4)}}}


={{{12c+12c}}}


={{{24c}}}