Question 683336
If the roots of the equation were 3 and 5, the factors would be x-3 and x-5 and the equation would be the product of the factors = (x-3)(x-5) = x^2 -8x +15.<P>
Subtract the roots from x to show the factors which are<P>
x-(-2+sqrt(6)) and x - (-2-sqrt(6)) = x+2-sqrt(6) and x+2+sqrt(6).  To find the equation multiply those factors together (multiply each term of the second factor by each term of the first factor).<P> 
{{{(x+2-sqrt(6))(x+2+sqrt(6)) = x^2 +2x +x*sqrt(6) +2x +4 +2*sqrt(6) -x*sqrt(6) -2*sqrt(6) -(sqrt(6))^2 = x^2 +4x -2}}} 
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