Question 683120
Please solve equation in radians for all exact solutions. Show all work
{{2√3cos(x/2)=-3}}
2√3cos(x/2)=-3
cos(x/2)=-3/(2√3)=-3√3/2*3=-√3/2
cos(x/2)=-√3/2
x/2=5&#960;/6+2&#960;k and 7&#960;/6+2&#960;k, k=integer (in quadrants II and III where cos<0)
x=5&#960;/3+2&#960;k and 7&#960;/3+2&#960;k, k=integer