Question 61519
given square root of 2x-1=x-2
squaring both sides we get
2x-1 = (x-2)^2
2x-1 = x^2 -4x +4   taking all the terms to one side
we get x^2-4x-2x+4+1=0
      x^2 -6x +5=0
splitting the middle term so that sum is -6 and product is 5 we get
      x^2-5x-x+5=0
     x(x-5)-1(x-5)=0
     (x-1)(x-5)=0
     x=1 or x=5 is the answer
good luck!!!