Question 683037
the sum of twice the square of the first number plus the second the number is 9. the difference between twice the first number and the second number is 15. Find the numbers?
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Equations:
2x^2 + y = 9
2x -  y = 15
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Add and solve for "x":
2x^2 = 24
x^2 = 12
x = 2sqrt(3)
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Solve for "y":
2x - y = 15
y = 2*2sqrt(3) + 15
y = 4sqrt(3) + 15
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Cheers,
Stan H.