Question 682947
{{{x^2-2x = 2}}}
...
{{{(-2/2)^2 = (-1)^2 = 1}}}
{{{x^2 - 2x + 1 = 2 + 1}}}
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{{{(x-1)^2 = 3}}}
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{{{sqrt(x-1)^2}}} = +/- {{{sqrt(3)}}}
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x-1 = +/- {{{sqrt(3)}}}
x = {{{1+-sqrt(3)}}}
...
{{{highlight_green(x = 1+sqrt(3))}}}
AND
{{{highlight_green(x=1-sqrt(3))}}}
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