Question 61468
State the coordinates of the vertex of the parabola whose equation is 
y = 3(x - 2)^2 + 5 

 (-2, -5)
 (-2, 5)
 (2, -5)
 (2, 5) <-- answer
 none of these
:
The vertex form of a quadratic eqution is:
{{{y=a(x-h)^2+k}}}, the vertex is (h,k)
In this case h=2 and k=5, the vertex is (h,k)=(2,5).
:
Happy Calculating!!!