Question 61443
3x^2-x-4 [use the quadratic formula to solve]
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
.
{{{x = (-(-1) +- sqrt( (1)^2-(4*3*-4) ))/(2*3) }}}[plug-in the values] 
{{{x = ((1 +- sqrt( (1-(148) ))/6)) }}}
{{{x = ((1) +- sqrt( 49))/6)) }}}
{{{x = ((1) + 7)/6)) }}}=1.333
{{{x = ((1) - 7)/6)) }}}=-1
.
So, x = -1 or x = 1.333