Question 682838
1.


{{{w^(-5) = 1/(w^5)}}} since {{{x^(-k) = 1/(x^k)}}} where k is some positive number.


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2.


{{{(d^(-3))^(-4) = d^(-3*(-4)) = d^(12)}}} Note: you multiply exponents in this case.


So {{{(d^(-3))^(-4) = d^(12)}}}