<PRE><B>Question 682673</B>
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ h)^2\ +\ (y\ -\ k)^2\ =\ r^2]


is a circle centered at *[tex \LARGE (h,\,k)] with radius *[tex \LARGE r].


It often helps to re-write the given equation, e.g.:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x\ -\ 3)^2\ +\ (y\ -\ (-9))^2\ =\ 3^2]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
&lt;font face=&quot;Math1&quot; size=&quot;+2&quot;&gt;Egw to Beta kai to Sigma&lt;/font&gt;
My calculator said it, I believe it, that settles it
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