<PRE><B>Question 682675</B>
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8 use both A and B, but that includes the 1 that uses all three, hence 7 use A and B only.


6 use both A and C, but that includes the 1 that uses all three, hence 5 use A and C only.


38 use A, but that includes the 7 that use A and B only, the 5 that use A and C only, and the 1 that uses all three, so 38 minus 7 minus 5 minus 1 = 25 use A only.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
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My calculator said it, I believe it, that settles it
&lt;div style=&quot;text-align:center&quot;&gt;&lt;a href=&quot;http://outcampaign.org/&quot; target=&quot;_blank&quot;&gt;&lt;img src=&quot;http://cdn.cloudfiles.mosso.com/c116811/scarlet_A.png&quot; border=&quot;0&quot; alt=&quot;The Out Campaign: Scarlet Letter of Atheism&quot; width=&quot;143&quot; height=&quot;122&quot; /&gt;&lt;/a&gt;&lt;/div&gt;
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