Question 682524
solve the equation for (x) over the interval of [0,360(degrees)]. 
4cos(2x)= sqrt( 3 )
cos(2x)=√3/4
2x=arccos√3/4
using calculator(cos^-1 key)
2x≈64.34º, 295.66º (in Q1 and Q4 where cos>0)
x≈32.17º, 147.83º