Question 61407
I think that one of the best ways of working algebra problems that contain fractions is first to get rid of the fractions and that's what we'll do.

2/3n+8=1/3n-1  Now, we get rid of the fractions by multiplying both sides by 3n
(2/3n)(3n)+8(3n)=(1/3n)(3n)-1(3n) simplifying, we get:
2+24n=1-3n further simplifying, we have
27n=-1
n=-1/27

Lets say that 2/5w=1/4  Here, we have two fractions to get rid of. By inspection, we see that the smallest number that both 4 and 5 divide evenly into is 20.  We could multiply both sides by 20 but that will not take care of the w so lets multiply both sides by 20w.
(2/5w)(20w)=(1/4)(20w) simplifying, we get
8=5w
w=8/5

Hope this helps------ptaylor