Question 682451
{{{(a)/(1+be^(-kt))= (a/2)}}}


{{{(a/(a/2))= (1+be^(-kt))}}}



{{{2=(1+be^(-kt))}}}

{{{2-1=be^(-kt)}}}

{{{(1/b) = e^(-kt)}}}


{{{log(1/b) = -kt*log(e)}}}

{{{(log(1/b))/(-k(log((e))))=t}}}