Question 682350


first writ  {{{2}}} and {{{2/3}}} as {{{2+2/3}}} or {{{6/3+2/3=8/3}}}


then divided by {{{1/3}}}


{{{(8/3)/(1/3)}}}..multiply outer terms of fractions and write a product as a nominator, and a product of inner terms as a denominator


={{{(8*3)/(3*1)}}}....simplify


={{{(8*cross(3))/(cross(3)*1)}}}


={{{8/1}}}


={{{8}}}