Question 682248
Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(1)+-sqrt((1)^2-4(10)(-3)))/(2(10))}}} Plug in {{{a = 10}}}, {{{b = 1}}}, {{{c = -3}}}


{{{x = (-1+-sqrt(1-(-120)))/(20)}}}


{{{x = (-1+-sqrt(1+120))/(20)}}}


{{{x = (-1+-sqrt(121))/20}}}


{{{x = (-1+sqrt(121))/20}}} or {{{x = (-1-sqrt(121))/20}}}


{{{x = (-1+11)/20}}} or {{{x = (-1-11)/20}}}


{{{x = 10/20}}} or {{{x = -12/20}}}


{{{x = 1/2}}} or {{{x = -3/5}}}