Question 682229
3 Options: if this is intentded to be {{{2x^2+4x+2=0}}}
Option 1. Use the Quadratic Formula
Option 2. Divide the entire equation by 2 and find factors
Option 3. After option 2, complete the square
...
Option 1
x = {{{(-4 +-sqrt(4^2-4(2)(2)))/(2*2)}}}
x = {{{(-4 +-sqrt(16-16))/4}}}
x = {{{(-4 +-0)/4}}}
x = -1
...
Option 2
{{{x^2 + 2x + 1 = 0}}}
(x+1)(x+1)=0
x+1=0
x = -1
...
Option 3
{{{x^2 + 2x + (2/2)^2)=-1 + (2/2)^2}}}
{{{x^2 + 2x + 1 = -1 + 1}}}
(x+1)^2 = 0
x = -1
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