<PRE><B>Question 682185</B>
The sum of the squares of two consecutive integer positive odd integers is equal to one hundred thirty. Find two integers.
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1st: 2x-1
2nd: 2x+1
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Equation:
(2x-1)^2 + (2x+1)^2 = 130
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4x^2 - 4x + 1 + 4x^2 + 4x + 1 = 130
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8x^2 = 128
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8(x^2 - 16) = 0
(x-4)(x+4) = 0
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x = 4 or x = -4
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If x = 4:
2x-1 = 7
2x+1 = 9
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If x = -4
2x-1 = -9
2x+1 = -7
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Cheers,
Stan H.
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