Question 61471
Find the vertex of the parabola whose equation in standard form is
 y = x2 + 8x - 1 
= [X^2+2(X)(4)+4^2]-4^2-1
=(X+4)^2-17
SO ITS VERTEX IS AT X=-4...AND Y=-17



(-8, -17)
(-8, -1)
(-4, -1)
(-4, -17)
(4, -17)