Question 682089
seven years ago varun's age was five times the square of swati's age. three years hence swati's age will be two fifth of varun's age.find their present ages
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let x=swati's present age
7 yrs ago
x-7=swati's age
5(x-7)^2=5(x^2-14x+49)=varun's age
..
3 yrs hence or 4 yrs ago
x-4=swati's age
5(x^2-14x+49)+3=varun's age
swati's age will be two fifth of varun's age
x-4=2/5*5(x^2-14x+49)
x-4=2(x^2-14x+49)
x-4=2x^2-28x+98
2x^2-29x+102=0
(2x-12)(x-8.5)=0
x=6(reject) swati wasn't born 7 yrs ago
x=8.5 (swati's present age)
5(x-7)^2+7=5(1.5)^2+7=18.25 (varun's present age)