Question 682081

Lina is twice as old as Ana while Laarni is 24 years younger than Lina.If half of Lina's age six years ago was three less than one-half the sum of Ana's age in four years and Laarni's present age,find the ages of each.


Let Ana’s current age be A
Then Lina’s is 2A
Laarni is 2A – 24
½(2A – 6) = ½(A + 4 + 2A – 24) - 3 
{{{(2A - 6)/2 = (3A - 20)/2 - 3}}}
2A – 6 = 3A – 20 – 6 ------ Multiplying by LCD, 2
2A – 3A = - 26 + 6 
- A = - 20
A, or Ana’s current age = {{{(- 20)/- 1}}}, or {{{highlight_green(20)}}}


Lina’s is 2(20), or {{{highlight_green(40)}}}


Laarni’s is 2(20) – 24, or 40 – 24, or {{{highlight_green(16)}}}


You should be able to do the check!!!


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