Question 682064
A=Android
B=Blackberry
i=iphone

Money wise:
i=595
A=195
B=150

3 equations
Amount of phones
{{{i+A+B=195}}}
{{{i=2A+2B}}}
money equation
{{{595i+195A+150B=88225}}}

so start with the first 2 equations
{{{(2A+2B)+A+B=195}}}
{{{3A+3B=195}}} lets solve for A
{{{3A=195-3B}}}
{{{A=65-B}}}
now use third equation and use what i and A equal
{{{595i+195A+150B=88225}}} first replace (i)
{{{595(2A+2B)+195A+150B=88225}}} now replace the (A)'s
{{{595(2(65-B)+2B)+195(65-B)+150B=88225}}} now solve for B
{{{595((130-2B)+2B)+(12675-195B)+150B=88225}}}
{{{595(130)+12675-40B=88225}}}
{{{77350+12675-40B=88225}}}
{{{90025-40B=88225}}}
{{{1800-40B=0}}}
{{{1800=40B}}}
{{{highlight(45=B)}}}
now you have B plug into the A equation {{{A=65-B}}}
{{{A=65-45}}}
{{{highlight(A=20)}}}
now you have A and B plug into {{{i=2A+2B}}}
{{{i=2(20)+2(45)}}}
{{{i=40+90}}}
{{{highlight(i=130)}}}
always check with last equation
{{{i+A+B=195}}}
{{{(130)+(20)+(45)=195}}}
{{{195=195}}} correct

hope this was helpful
~jbarnum~