Question 682044
{{{(x^3 + 27)/(x+3)}}}
...
x+3 goes into {{{x^3 + 27}}} : x^2
to get
{{{x^3 + 3x^2}}}
subtracting
{{{x^3 - x^3 + 27 - 3x^2}}}
yielding
{{{-3x^2+27}}}
...
The remainder factors as
-3(x^2-9)
-3(x+3)(x-3)
...
{{{(x^3+27)/(x+3) = x^2}}}{{{(-3(x+3)(x-3))/(x+3)}}}
...
{{{(x^2)(-3(x-3))}}}
...
{{{(x^2)(-3x+9)}}}
Resulting in:
{{{-3x^3+9x^2}}} = {{{-3x^2(x-3)}}}
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