<PRE><B>Question 681899</B>
Three cards are drawn at random from an ordinary pack of cards. Find the probability that they will consist of a king, a queen and an ace
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# of ways to succeed = 4*4*4 = 64
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# of possible triples: 52C3 = (52*51*50)/(1*2*3) = 22100
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P(condition) = 64/22100 = 0.0029
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Cheers,
Stan H.</PRE>