Question 681983
let the length be x and the width be y.
from the question, we have
2(x+y)=48
x=y+6
by substituting the second equaation into the first equaation, we have
2[(y+6)+y)=48
  2[y+6+y]=48
   2[2y+6]=48
    4[y+3]=48
       y+3=12
      {{{y=9}}}
by substituting y=9 into the second equaation, we have
   x=9+6
{{{x=15}}}

the length of the rectangle is 15 inches and the width of the rectangle is 9 inches.