Question 681907
let the first number be x,the second number be y, and the third number be z.
from the question, we have
x+y+z=118
y=x-17
z=3x+5
by substituting the second and the third equation into the first equation, we have
x+(x-17)+(3x+5)=118
    x+x-17+3x+5=118
          5x-12=118
             5x=130
           {{{x=26}}}
by substituting x=26 into the second equation, we have
          y=(26)-17
       {{{y=9}}}
by substituting x=26 into the third equation, we have
         z=3(26)+5
         z=78+5
      {{{z=83}}}

checking:
by substituting x=26, y=9, and z=83 into the first equation, we have
(26)+(9)+(83)
=118

the three numbers are 26,9,and 83.